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(140x-x^2-2000)=0
We get rid of parentheses
-x^2+140x-2000=0
We add all the numbers together, and all the variables
-1x^2+140x-2000=0
a = -1; b = 140; c = -2000;
Δ = b2-4ac
Δ = 1402-4·(-1)·(-2000)
Δ = 11600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11600}=\sqrt{400*29}=\sqrt{400}*\sqrt{29}=20\sqrt{29}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(140)-20\sqrt{29}}{2*-1}=\frac{-140-20\sqrt{29}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(140)+20\sqrt{29}}{2*-1}=\frac{-140+20\sqrt{29}}{-2} $
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